Answer: The molarity of iron(II) bromide solution is 3.46 M
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Given mass of iron(II) bromide = 224. g
Molar mass of iron(II) bromide = 215.65 g/mol
Volume of solution = 300. mL
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{224\times 1000}{215.65g/mol\times 300}\\\\\text{Molarity of solution}=3.46M[/tex]
Hence, the molarity of iron(II) bromide solution is 3.46 M
