Respuesta :
Answer:
The cpp program for the given scenario is shown below.
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
//variables to store length and breadth of the rectangle frame
double length;
double breadth;
//variable to store the length of the wire
double len;
//user prompted to enter the length of the wire
cout<<"Enter the length of the wire: ";
cin>>len;
//computing length of the rectangle frame using area formula
length = len/4.5;
//breadth of the rectangle frame as per given data
breadth = 1.5 * length;
//displaying dimensions of the rectangle frame
cout << "The length and breadth of the picture frame are "<< setprecision(3) << length <<" and "<< setprecision(3) << breadth <<" respectively. "<<endl;
return 0;
}
OUTPUT
Enter the length of the wire: 20
The length and breadth of the picture frame are 4.44 and 6.67 respectively.
Explanation:
The program works as described.
1. The variables are declared to store the length and breadth of the rectangle frame and to store the length of the wire.
2. The user is prompted to input the length of the wire, len, as per the question.
3. The length and breadth of the rectangle are calculated using the following steps.
2*(length + breadth) = len
length + (1.5 * length) = len/2
2.5length = len/2
length = len/4.5
4. The dimensions of the rectangle frame are displayed to the user. All the dimensions are displayed with two decimal places. The formatting is done using setprecision(n) where n is the total number of digits required in the output. The value of n can be changed. For the setprecision(n) method, iomanip header file is included.
5. All the variables are declared as double to accommodate all types of numeric values.
6. The program ends with a return statement.
7. The dimensions have no units since this is not mentioned in the question.
8. All coding is written inside main().
