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Calculate the molarity of the solutions described below.
A. 10.0 g of sodium chloride is dissolved in 2.0 L of solution.

B. 52.5 g of sugar (C12H22O11) s dissolved in 1.0 L of solution.

C. 120 g of aluminum sulfate is dissolved in 10.0 L of solution.

D. 1.75 g of caffeine (C8H10N4O2) is dissolved in 0.100 L of solution.

Respuesta :

Answer:

Explanation:

A. Na = 23 g/m  Cl = 35.5 g/m NaCl = 58.5 g/m

10g / 58.5 g/m = .17 mole

.17 mole/ 2.0 L = 0.086 m/L = 0.086 Molar

B.  342 g/m      52.5/342 =0.15 mole     0.15 mole/1.0 L = 0.15 Molar

C. Al2(SO4)3== 342 g/m   120/342 = 0.35 mole  0.35 m/10.L  0.035 Molar

D caffeine = 194 g/m   1.75/ 194 = 0.009 mole  0.009/0.100 L  0.09 Molar

a.  0.086 Molar

b. 0.15 Molar

c. 0.035 Molar

d. 0.09 Molar

Calculation of molarity of the following solutions:

A.

Since 10.0 g of sodium chloride is dissolved in 2.0 L of solution.

So,

Na = 23 g/m  Cl = 35.5 g/m NaCl = 58.5 g/m

Now

10g / 58.5 g/m = .17 mole

And,

.17 mole/ 2.0 L = 0.086 m/L = 0.086 Molar

B. Since 52.5 g of sugar (C12H22O11) s dissolved in 1.0 L of solution.

Now  it is 342 g/m  

So,    52.5/342 =0.15 mole    

= 0.15 mole/1.0 L

= 0.15 Molar

C. Since 120 g of aluminum sulfate is dissolved in 10.0 L of solution.

So, Al2(SO4)3= 342 g/m  

So,

120/342 = 0.35 mole

Now

=  0.35 m/10.L  

= 0.035 Molar

D Since . 1.75 g of caffeine (C8H10N4O2) is dissolved in 0.100 L of solution.

Now

caffeine = 194 g/m  

=  1.75/ 194 = 0.009 mole

Now

=  0.009/0.100 L  

= 0.09 Molar

learn more about the sugar here: https://brainly.com/question/20088453