To solve this problem we will apply the concept related to the electric field as a function of the charge, the area and the permittivity constant of free space. This is mathematically defined as
[tex]E= \frac{Q}{A\epsilon_0}[/tex]
Here,
Q= Charge
A = Area
[tex]\epsilon_0[/tex] = Permittivity of free space
Rearranging to find the charge,
[tex]Q = A\epsilon_0 E[/tex]
Replacing,
[tex]Q = (7.2*10^{-2})^2 (8.85*10^{-12})(3*10^6)[/tex]
[tex]Q = 1.37635*10^{-7}C[/tex]
Therefore the charge is [tex]1.37*10^{-7}C[/tex]
