Respuesta :
Answer : The incorrect option is, (d) [tex]NH_4^+/NH_2^-[/tex]
Explanation :
According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.
Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.
(a) The equilibrium reaction will be,
[tex]HF+H_2O\rightleftharpoons F^-+H_3O^+[/tex]
In this reaction, [tex]HF[/tex] is an acid that donate a proton or hydrogen to [tex]H_2O[/tex] base and it forms [tex]F^-[/tex] and [tex]H_3O^+[/tex] are conjugate base and acid respectively.
In this reaction, [tex]HF/F^-[/tex] are act as a conjugate acid-base.
(b) The equilibrium reaction will be,
[tex]HClO+H_2O\rightleftharpoons ClO^-+H_3O^+[/tex]
In this reaction, [tex]HClO[/tex] is an acid that donate a proton or hydrogen to [tex]H_2O[/tex] base and it forms [tex]ClO^-[/tex] and [tex]H_3O^+[/tex] are conjugate base and acid respectively.
In this reaction, [tex]HClO/ClO^-[/tex] are act as a conjugate acid-base.
(c) The equilibrium reaction will be,
[tex]H_2O+H_2O\rightleftharpoons OH^-+H_3O^+[/tex]
In this reaction, [tex]H_2O[/tex] is an acid that donate a proton or hydrogen to
In this reaction, [tex]H_2O/OH^-[/tex] are act as a conjugate acid-base.
(d) The equilibrium reaction will be,
[tex]NH_4^++H_2O\rightleftharpoons NH_3+H_3O^+[/tex]
In this reaction, [tex]NH_4^+[/tex] is an acid that donate a proton or hydrogen to [tex]H_2O[/tex] base and it forms [tex]NH_3[/tex] and [tex]H_3O^+[/tex] are conjugate base and acid respectively.
In this reaction, [tex]NH_4^+/NH_3[/tex] are act as a conjugate acid-base.
(e) The equilibrium reaction will be,
[tex]H_3O^++H_2O\rightleftharpoons H_2O+H_3O^+[/tex]
In this reaction, [tex]H_3O^+[/tex] is an acid that donate a proton or hydrogen to [tex]H_2O[/tex] base and it forms
In this reaction, [tex]H_3O^+/H_2O[/tex] are act as a conjugate acid-base.
From this we conclude that that, [tex]NH_4^+/NH_2^-[/tex] pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched.
Hence, the incorrect option is, (d) [tex]NH_4^+/NH_2^-[/tex]