contestada

A gun has a muzzle speed of 150 m/s. Find two angles of elevation that can be used to hit a target 800m away.

Respuesta :

Answer:

Explanation:

u =  150 m/s

R = 800 m

The formula for the horizontal range is

[tex]R=\frac{u^{2}Sin2\theta }{g}[/tex]

where, θ is angle of projection.

[tex]800=\frac{150^{2}Sin2\theta }{9.8}[/tex]

Sin2θ = 0.348

2θ = 20.4°

θ = 10.2°

The range is same for the complementary angles.

So, the other angle is 90 - 10.2 = 79.8°