Answer:
The total volume of concrete will be [tex]135\ ft^3[/tex]
Step-by-step explanation:
Given the dimensions of the diagram.
Let us divide the diagram into two diagram. Diagram-1 and Diagram-2
The dimensions of Diagram-1 will be. (See attachment)
Length [tex]9\ ft[/tex], Height [tex]1.5\ ft[/tex] , And width [tex]6\ ft[/tex].
Then the volume of Diagram-1 will be
[tex]V_1=l\times w\times h\\V_1=9\times 6\times 1.5\\V_1=81\ ft^3[/tex]
Now, the dimensions of Diagram-2 will be. (See attachment)
Length [tex]6\ ft[/tex], Height [tex]1.5\ ft[/tex], And width
Then the volume of Diagram-2 will be
[tex]V_2=l\times w\times h\\V_2=6\times 6\times 1.5\\V_2=54\ ft^3[/tex]
So, the total volume will be
[tex]V=V_1+V_2\\V=81+54\\V=135\ ft^3[/tex]
So, [tex]135\ ft^3[/tex] of concrete will required.