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A person standing on a building ledge throws a ball vertically from a launch position 51 m above the ground. It takes 2.0 s for the ball to hit the ground.

With what initial speed was the ball thrown?

Express your answer with the appropriate units. Enter positive value if the initial speed is upward and negative value if the initial speed is downward.

Respuesta :

Answer:

56 m

Explanation:

if you do the math it will add up

onyebuchinnaji

The initial velocity of the ball when it was thrown vertically downwards is 15.7 m/s.

The given parameters;

  • Height above the ground, h = 51 m
  • Time of motion of the ball, t = 2 s

The initial velocity of the ball when it was thrown vertically downwards is calculated as;

h = ut + ¹/₂gt²

51 = 2u + (0.5 x 9.8 x 2²)

51 = 2u + 19.6

2u = 51 - 19.6

2u = 31.4

[tex]u = \frac{31.4}{2} \\\\u = 15.7 \ m/s[/tex]

Thus, the initial velocity of the ball when it was thrown vertically downwards is 15.7 m/s.

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