Answer:
12 and 52
Step-by-step explanation:
Let x and y be the 2 integers with x > y, then
x + y = 64 and
x = 3y + 16 ( 16 more than 3 times the smaller )
Substitute x = 3y + 16 into x + y = 64, that is
3y + 16 + y = 64
4y + 16 = 64 ( subtract 16 from both sides )
4y = 48 ( divide both sides by 4 )
y = 12 and x = 3(12) + 16 = 36 + 16 = 52
The 2 integers are 12 and 52
