Answer:
The drama club must sold at least 142 bottles of water in addition the the 144 cans of lemonade already sold, to cover the cost of renting costumes.
Correct statement and question:
The drama club is running a lemonade stand to raise money for its new production. A local grocery store donated cans of lemonade and bottles of water. Cans of lemonade sell for $2 each and bottles of water sell for $1.50 each. The club needs to raise at least $500 to cover the cost of renting costumes. The students can accept a maximum of 360 cans and bottles.
Write a system of inequalities that can be used to represent this situation.
The club sells 144 cans of lemonade. What is the least number of bottles of water that must be sold to cover the cost of renting costumes? Justify your answer.
Source: (Written not in the original form because it was rejected by Brainly)
mr burke math blog spot com /2018 /02 /january-2018-common-core-algebra-i_2. html
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Cost of lemonade can = $ 2
Cost of water bottle = $ 1.50
Cost of renting costumes = $ 500
The students can accept a maximum of 360 cans and bottles
Cans of lemonade sold = 144
2. Write a system of inequalities that can be used to represent this situation.
w = bottle of water
l = can of lemonade
2l + 1.5w ≥ 500
w + l ≤ 360
3. What is the least number of bottles of water that must be sold to cover the cost of renting costumes? Justify your answer.
Replacing l with 144, that were the cans sold, on the 1st inequality
2l + 1.5w ≥ 500
2(144) + 1.5w ≥ 500
288 + 1.5w ≥ 500
1.5w ≥ 500 - 288
1.5w ≥ 212
w ≥ 212/1.5
w ≥ 141.33
The drama club must sold at least 142 bottles of water in addition the the 144 cans of lemonade already sold, to cover the cost of renting costumes.
