Respuesta :
Answer: The volume of solution is 1.13 L
Explanation:
To calculate the volume of solution, we use the equation used to calculate the molarity of solution:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]
We are given:
Molarity of solution = 2.09 M
Given mass of silver nitrate = 400. g
Molar mass of silver nitrate = 170 g/mol
Putting values in above equation, we get:
[tex]2.09M=\frac{400}{170\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{400}{170\times 2.09}=1.13L[/tex]
Hence, the volume of solution is 1.13 L
Answer:
The volume is 1.13 *10³ mL
Explanation:
Step 1: Data given
Molarity of silvernitrate = 2.09 M
Mass of silvernitrate = 400 grams
Molar mass of silvernitrate = 169.87 g/mol
Step 2: Calculate number of moles
Number of moles = mass silvernitratre / molar mass silvernitrate
Number of moles = 400.0 grams / 169.87 g/mol
Number of moles = 2.355 moles
Step 3: Calculate volume
Molarity = moles / volume
Volume = moles / molarity
Volume = 2.355 moles / 2.09 M
Volume = 1.13 L = 1130 mL = 1.13 *10³ mL
The volume is 1.13 *10³ mL
