Answer:
porosity=23.07%
x=5.974*10^9cm^3
Explanation:
One liter of oven-dry soil sampled from the Chorro Creek Ranch field requires 300 g of water to completely saturate it.
Calculate (a) its porosity, n, and (b) the volume of water required to saturate the top 20 cm of 1 hectare of the field.
-Porosity of a soil sample can be calculated in five ways but i shall use the formula below
porosity=[tex]\frac{volume of pore}{volume of total} *100%[/tex]%
volume pore volume of sample is equal to water volume used to saturate the soil
total volume=sample volume +pore volume
1L=1000cm^3
density of water=density=mass/volume
1g/cm^3=300g/volume
vol=300cm^3
total volume=300+1000
1300
porosity =(300/1300)*100%
porosity=23.07%
2. Recall that volume=area *height
1 hectare=1*10^9cm^2
the volume of soil sample=1*10^9cm^2*20cm
2*10^10cm^3
[tex]porosity=\frac{x}{x+2*10^{10} } *100%[/tex]%
23%=x/(x+2*10^10)*100%
x=5.974*10^9cm^3