A fair die is rolled and the sample space is given S={1,2,3,4,5,6}. Let A={1,2} and B={3,4}. Which of the following statements is true?

a. A and B are mutually exclusive
b. P(A or B)=4/6.
c. P(A or B) = P(A)+P(B).
d. All of the choices are correct.

Respuesta :

All of the choices are correct, therefore the correct option is d.

Given:

The given sets are:

[tex]S=\{1,2,3,4,5,6\}[/tex]

[tex]A=\{1,2\}[/tex]

[tex]B=\{3,4\}[/tex]

To find:

The correct statement for the given sets.

Explanation:

Two sets are mutually exclusive if they have no common elements.

Clearly, the set A and set B have no common elements. So, A and B are mutually exclusive. The union of set A and set B is:

[tex]A\text{ or }B=\{1,2,3,4\}[/tex]

Now,

[tex]n(A\text{ or }B)=4[/tex]

[tex]n(S)=6[/tex]

[tex]P(A\text{ or }B)=\dfrac{n(A\text{ or }B)}{n(S)}[/tex]

[tex]P(A\text{ or }B)=\dfrac{4}{6}[/tex]

And,

[tex]P(A)+P(B)=\dfrac{2}{6}+\dfrac{2}{6}[/tex]

[tex]P(A)+P(B)=\dfrac{2+2}{6}[/tex]

[tex]P(A)+P(B)=\dfrac{4}{6}[/tex]

[tex]P(A)+P(B)=P(A\text{ or }B)[/tex]  

Since all of the choices are correct, therefore the correct option is d.

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