Respuesta :
Answer:
Electric field, [tex]E=10^{-7}\ N/C[/tex]
Explanation:
It is given that, a proton in a particular electric field experiences an electric force whose magnitude is equal to the weight of the proton such that,
[tex]qE=mg[/tex]
[tex]E=\dfrac{mg}{q}[/tex]
[tex]E=\dfrac{1.67\times 10^{-27}\times 9.8}{1.6\times 10^{-19}}[/tex]
[tex]E=1.02\times 10^{-7}\ N/C[/tex]
or
[tex]E=10^{-7}\ N/C[/tex]
So, the magnitude of electric field at the location of the proton is [tex]10^{-7}\ N/C[/tex]. Hence, this is the required solution.
