Respuesta :

Answer:

aluminum bar carrying a higher load than steel bar

Explanation:

Given data;

steel abr

diameter = 5 mm

stress = 500 MPa

aluminium bar

diameter = 10 mm

stress = 150 MPa

we know

stress = laod/area

for steel bar

[tex]500 = \frac{P}{\frac{\pi}{4} 5^2}[/tex]

solving for P

P = 9817.47 N

for Aluminium bar

[tex]150 = \frac{P}{\frac{\pi}{4} 10^2}[/tex]

solving for P

P = 11790 N

aluminum bar carrying a higher load than steel bar

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