Answer : The time taken for a 50 µF capacitor to fully charge if it is in a series circuit with a 100 KΩ resistor is, 0.5 seconds.
Explanation :
RC time constant is the time constant (in seconds). It is equal to the product of the circuit resistance (in ohms) and the circuit capacitance (in farads).
The formula will be:
[tex]\tau=R\times C[/tex]
where,
[tex]\tau[/tex] = time constant = ?
R = resistance = 100 KΩ = 100000 Ω
Conversion used : (1 KΩ = 1000 Ω)
C = capacitance = 50 μF = 50 × 10⁻⁶ F
Conversion used : (1 μF = 10⁻⁶ F)
Now put all the given values in the above formula, we get:
[tex]\tau=(100000\Omega)\times (50\times 10^{-6}F)[/tex]
[tex]\tau=0.5s[/tex]
Thus, the time taken for a 50 µF capacitor to fully charge if it is in a series circuit with a 100 KΩ resistor is, 0.5 seconds.
This question involves the concepts of the charging time of a capacitor. It involves the use of RC Equation.
The capacitor will take "5 s" to fully charge.
We will use the simple RC equation formula to find out the charging time required by the capacitor to fully charge.
[tex]T = RC[/tex]
where,
T = charging time = ?
R = Resistance connected in series = 100 KΩ = 1 x 10⁵ Ω
C = Capacitance of the capacitor = 50 μF = 5 x 10⁻⁵ F
Therefore,
[tex]T = (1\ x\ 10^5 \Omega)(5\ x\ 10^{-5}\ F)[/tex]
T = 5 s
Learn more about the charging time of a capacitor here:
https://brainly.com/question/13019277?referrer=searchResults
The attached picture shows the charging time equation of the capacitor.
