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Consider as a system the gas in a vertical cylinder; the cylinder is fitted with a piston onwhich a number of small weights are placed. The initial pressure is 200 kPa, and the initial volume ofthe gas is 0.04 m^3. Let a bunsen burner be placed under the cylinder, and let thevolume of the gas increase 0.1m^3 while the pressure remainsconstant.
A. Calculate the work done by the system during this process.

Respuesta :

Answer:

Work done = 12,000J = 12KJ

Explanation:

This process is an Isobaric one i.e a process at constant pressure

  • P = 200KPa = 200 x 1000 Pa = 200,000Pa
  • Vi = 0.04m3
  • Vf = 0.1m3

From the formula for Workdone = Integral (PdV)

Work done = P ( Vf - Vi)

Plugging the values in the equation,

Work done = 200,000 ( 0.1 - 0.04)

Work done = 12,000J = 12KJ