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Consider that you have a 100 mM stock solution and you need to prepare 10 mL of a 30 mM solution. How many milliliters of the stock solution do you need? mL How many milliliters of deionized water do you need? mL

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dsdrajlin

Answer:

V₁ = 3.0 mL

V(H₂O) = 7 mL

Explanation:

Given data

  • Initial concentration (C₁): 100 mM
  • Initial volume (V₁): ?
  • Final concentration (C₂): 30 mM
  • Final volume (V₂): 10 mL

In order to determine the volume of the stock solution, we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

100 mM × V₁ = 30 mM × 10 mL

V₁ = 3.0 mL

The volume of deionized water required is:

V(H₂O) = 10 mL - 3.0 mL = 7 mL

pstnonsonjoku

The volume of the stock solution required is 3 mL.

The stock solution is defined as the solution from which other solutions are prepared. We have the following information;

  • concentration of stock solution = 100 mM
  • Concentration of diluted solution = 30 mM
  • Volume of diluted solution = 10 mL

Using the formula;

M1V1 = M2V2

V1 = M2V2/M1

V1 = 30mM × 10 mL/100 mL

V1 = 3 mL

The volume of the stock solution required is 3 mL.

Learn more about dilution formula: https://brainly.com/question/7208939