Respuesta :

2.54 moles of CaCl occupies 56.89 liters volume

Explanation:

  • Each mole of any gas occupies 22.4 liters volume at STP.
  • STP is defined as the standard temperature and pressure and those standard values are zero degree and one atmospherics pressure
  • 22.4 liters is a constant number as Avogadro's number which is nothing but 6.022* [tex]10^{23}[/tex] .
  • Hence, to convert 2.54 moles just multiply it with 22.4 L
  • That is, 22.4*2.54= 56.89 L
  • So, 2.54 moles of CaCl occupies 56.89 L volume space

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