Answer:
y=1/6 · ln |x|+c .
Step-by-step explanation:
From Exercise we have the differential equation
4xy dx= (4y6x²) dy.
We calculate the given differential equation, we get
4xy dx= (4y6x²) dy
xy dx=6yx² dy
6 dy=1/x dx
∫ 6 dy=∫ 1/x dx
6y=ln |x|+c
y=1/6 · ln |x|+c
Therefore, we get that the solution of the given differential equation is
y=1/6 · ln |x|+c .
