Answer:
Magnitude of resultant vector will be 4.643 N
Explanation:
We have given x-component of the force vector is given [tex]F_{X}=2.16N[/tex]
And y component of the force vector is given [tex]F_{y}=4.11N[/tex]
We have to find the magnitude of resultant force F
Resultant force will be equal to vector sum of magnitude of x competent and y component of force vector
So F = [tex]\sqrt{F_X^2+F_Y^2}=\sqrt{2.16^2+4.11^2}=4.643N[/tex]
So magnitude of resultant vector will be 4.643 N
