Answer:
[tex]a=-2m/sec^2[/tex]
Negative sign shows that velocity of the car is decreases at a constant rate
Explanation:
We have given velocity of the car is decreases from 32 m /sec to 24 m/sec in 4 second
So initial velocity of the car u = 32 m /sec
And finally car reaches to a velocity of 24 m/sec
Time taken to change in velocity = 4 sec
So final velocity v = 24 m/sec
From first equation of motion v = u+at
So [tex]24=32+a\times 4[/tex]
[tex]a=-2m/sec^2[/tex]
Negative sign shows that velocity of the car is decreases at a constant rate
