Answer:[tex]44.1\times 10^6[/tex] atoms
Explanation:
According to the ideal gas equation:
[tex]PV=nRT[/tex]
P = Pressure of the gas = [tex]1.83\times 10^{-7}N/m^2=1.81\times 10^{-12}atm[/tex] [tex]1N/m^2=9.87\times 10^{-6}atm[/tex]
V= Volume of the gas = [tex]1cm^3=1ml=0.001L[/tex] (1L=1000ml)
T= Temperature of the gas = 28°C = 301 K [tex]0^0C=273K[/tex]
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= ?
[tex]n=\frac{PV}{RT}=\frac{1.81\times 10^{-12}atm\times 0.001L}0.0821Latm/Kmol\times 301K}=7.32\times 10^{-17}moles[/tex]
Number of atoms =[tex]moles\times {\text {avogadro's number}}=7.32\times 10^{-17}mol\times 6.023\times 10^{23}mol^{-1}=44.1\times 10^6atoms[/tex]
Thus there are [tex]44.1\times 10^6[/tex] atoms in a cubic centimeter at this pressure and temperature.
