Respuesta :
Applying
v=u+a.t
(all the symbols are bearing their conventional meaning)
Here,u=2ms−1,t=5,a=4ms−2
So,v=2+4⋅5=22ms−1
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Answer:
22m/s
Explanation:
V = u + at
= 2 + ( 4x5)
= 2 + 20
= 22m/s
Applying
v=u+a.t
(all the symbols are bearing their conventional meaning)
Here,u=2ms−1,t=5,a=4ms−2
So,v=2+4⋅5=22ms−1
Answer:
22m/s
Explanation:
V = u + at
= 2 + ( 4x5)
= 2 + 20
= 22m/s