Answer:
a) 1.24*10¹⁰ . b) 3.11*10¹²
Explanation:
The charge is quantized, so any charge is a multiple of the elementary charge e, which is the charge of one electron (being negative) or a proton (if it is positive).
The value of e is 1.61*10⁻¹⁹ coulombs.
a) So, if we need to form a charge of -2.00 nC, this will be equal to the following expression:
Q = -2.00 nC = n*e = n*(-1.61*10⁻¹⁹) C
Solving for n, replacing nC by 10⁻⁹ C, we have:
n=- 2*10⁻9 C /- 1.61.10⁻¹⁹ C = 1.24*10¹⁰ electrons.
b) In the same way, we get the number of electrons (as a negative charge) that it is needed to remove from a neutral object to leave a net charge of 0.500 μC = 5*10⁻⁷ C, as follows:
n = -5*10⁻⁷ C / -1.61*10⁻¹⁹ C =3.11*10¹² electrons.
In the first case there are 1.25 × 10^10 electrons in the second case, there are 3.1 × 10^12 electrons.
.
Static electricity is usually composed of electric charges of very small magnitude such as nanocoulombs to microcoulombs.
For question (a)
Q = ne
Q= magnitude of electric charge
n = number of electrons
e = magnitude of electronic charge
2 × 10^-9 C = n1.6 × 10^-19C
n = 2 × 10^-9 C/1.6 × 10^-19C
n = 1.25 × 10^10 electrons
For question (b)
0.5 × 10^-6 = n1.6 × 10^-19C
n = 0.5 × 10^-6/1.6 × 10^-19C
n = 3.1 × 10^12 electrons
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