krazecat krazecat

28-01-2020
Mathematics

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Find DC

HELP PLEASE!! :(
using sine cosine or tangent

Find DC HELP PLEASE using sine cosine or tangent class=

Respuesta :

joshnajd joshnajd

02-02-2020

DC=14

Explanation

consider triangle ADB

<BAD=54°

sin<BAD=opposite side/ hypotenuse

sin 54°=BD/BA

BD=BA sin 54°=20*0.8=16

consider triangle BDC

cos <BCD=adjacent side/hypotenuse

=DC/BC

cos 28°=DC/BC

DC=cos28° *BC

=0.88*16=14.08

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