Answer:
47.5 g of water can be formed
Explanation:
This is the reaction:
CH₄ + 2O₂ → CO₂ + 2H₂O
Methane combustion.
In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.
As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.
1.320 mol .2 = 2.64 moles
Now, we can convert the moles to mass (mol . molar mass)
2.64 mol . 18g/mol = 47.5 g
Answer:
mass H2O = 47.56 g
Explanation:
balanced reation:
∴ moles CH4 = 1.320 mol
⇒ moles H2O = (1.320 mol CH4)×(2 mol H2O/mol CH4)
⇒ moles H2O = 2.64 mol H2O
∴ molar mass (mm) H2O = 18.015 g/mol
⇒ mass H2O = (2.64 mol H2O)×(18.015 g/mol)
⇒ mass H2O = 47.56 g
