Answer:12
Step-by-step explanation:
Let the numbers be a and b
a-3b=5 ........equation (1)
There product is :
ab=68 ..........equation (2)
From equation (1)
a-3b=5
Make a the subject of the formula
a=5+3b. ........equation (3)
Substitute equation (3) into equation (2)
(5+3b)b=68
3(b^2)+3b-68=0
The product is -204b^2(17 and -12)
(b+17)(b-12)=0
b=-17 or b=12
So the number is 12
First and another number is 4 and 17
Product of two number = 68
Numbers
Assume;
First number = a
So, Another number = 3a + 5
[a][3a + 5] = 68
3a² + 5a = 68
3a² + 5a - 68 = 0
3a² + 17a - 12a - 68 = 0
3a(a - 4) + 17(a - 4)
So,
a = 4
First number = 4
So, Another number = 3a + 5 = 3(4) + 5 = 17
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