Answer: 0.07meter
Pointing to the left.
Explanation:
The Electric potential V of the proton is 3.8v. while the Electric Field strength is 56V/m. We first calculate the distance r the proton would travel
E= V/r
r = V/E
r = 3.8V/(56V/m)
r =0.07m.
The proton which is positively charged will move in the direction of the Electric Field that is to the left.
