There are some placeholders in the expression, but they can be safely assumed
Answer:
(a) [tex]f=1617.9\ Hz[/tex]
(b) [tex]T=0.618\ ms[/tex]
(c) [tex]A=20 \ Volts[/tex]
(d) [tex]\varphi=60^o[/tex]
Explanation:
Sinusoidal Waves
An oscillating wave can be expressed as a sinusoidal function as follows
[tex]V(t)&=A\cdot \sin(2\pi ft+\varphi )[/tex]
Where
[tex]A=Amplitude[/tex]
[tex]f=frequency[/tex]
[tex]\varphi=Phase\ angle[/tex]
The voltage of the question is the sinusoid expression
[tex]V(t)=20cos(5\pi\times 103t+60^o)[/tex]
(a) By comparing with the general formula we have
[tex]f=5\pi\times 103=1617.9\ Hz[/tex]
[tex]\boxed{f=1617.9\ Hz}[/tex]
(b) The period is the reciprocal of the frequency:
[tex]\displaystyle T=\frac{1}{f}[/tex]
[tex]\displaystyle T=\frac{1}{1617.9\ Hz}=0.000618\ sec[/tex]
Converting to milliseconds
[tex]\boxed{T=0.618\ ms}[/tex]
(c) The amplitude is
[tex]\boxed{A=20 \ Volts}[/tex]
(d) Phase angle:
[tex]\boxed{\varphi=60^o}[/tex]
