Answer:
- [tex]\large\boxed {1.59 mm}[/tex]
Explanation:
1. Given vector:
- length: 4.00 mm = magnitude of the vector
- angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)
2. y-component
The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.
- sine (23.5º) = y-component / magnitude
- y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.
- [tex]\large\boxed{y-component = 1.59 mm}[/tex]
