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A real gas is in a regime in which it is accurately described by the ideal gas equation of state. 27.1 g of the gas occupies 50.0 L at a pressure of 0.500 atm and a temperature of 449 K. Identify the gas.

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dsdrajlin

Answer:

Argon

Explanation:

Given data

  • Mass (m): 27.1 g
  • Volume (V): 50.0 L
  • Pressure (P): 0.500 atm
  • Temperature (T): 449 K

We can find the molar mass (M) of the gas using the ideal gas equation.

P × V = n × R × T

P × V = m/M × R × T

M = m × R × T/P × V

M = 27.1 g × (0.08206 atm.L/mol.K) × 449 K/ 0.500 atm × 50.0 L

M = 39.9 g/mol

If the gas is monoatomic, the one with a molar mass of 39.9 g/mol is argon.

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