Respuesta :
Answer:
The charge is 0.056 nC.
Explanation:
Given that,
Electric field = 2000 N/C
Distance = 5.0 cm
We need to calculate the charge density
Using formula of charge density
[tex]E=\dfrac{\lambda}{2\pi\times\epsilon_{0}r}[/tex]
[tex]\lambda=2\pi\times\epsilon_{0}\times r\times E[/tex]
Put the value into the formula
[tex]\lambda=2\pi\times8.85\times10^{-12}\times5.0\times10^{-2}\times2000[/tex]
[tex]\lambda=5.56\times10^{-9}\ C/m[/tex]
We need to calculate the charge in 1.0 cm
Using formula of charge
[tex]Charge = \lambda\times\text{length of segment}[/tex]
[tex]Charge =5.56\times10^{-9}\times1.0\times10^{-2}[/tex]
[tex]Charge=0.056\times10^{-9}\ C[/tex]
[tex]Charge=0.056\ nC[/tex]
Hence, The charge is 0.056 nC.
The charge on a 1.0-cm-long segment of the wire is -1.11 nC.
Let us assume the electric field be E.
It is given that at a distance r = 5cm = 0.05 m , the value of electric field is 2000N/C.
Since the field is directed towards the wire, the wire must be negatively charged.
Let the linear charge density of the wire be λ. So to calculate the charge in l length of a line segment, the charge would be :
q = λl
Now the electric field E at a distance of r due to a long charged wire is given by:
E = λ/2πε₀r
λ = 2πε₀rE
λ = -2×3.14×8.85×10⁻¹²×2000
λ = -1.11×10⁻⁷ N/m
So in 1 cm segment charge q:
q = -1.11×10⁻⁷ N/m × 1×10⁻²m
q = -1.11×10⁻⁹ C
-1.11 nC will be the charge in 1cm segment of wire.
Learn more:
https://brainly.com/question/18156924
