The circular blade on a saw has a diameter of 6.25 inches and rotates at 4500 revolutions per minute. (a) Find the angular speed of the blade in radians per minute. (Round your answer to three decimal places.)

Respuesta :

Answer:angular speed=471.429rad/sec

Step-by-step explanation:

One revolution is :

2×pi×radians

Then 4500 revolution will be:

2×pi×4500rad= 9000pi rad

1minutes = 60seconds

So the angular speed is :

=(9000×pi rad) / minutes

=9000×(22/7)rad /60seconds

=471.42857143 rad/sec

=471.429rad/sec to 3 d.p

The angular speed of the blade is [tex]471[/tex] radian per minute.

In one revolution, angle made is [tex]2\pi[/tex] radian.

In 4500 revolutions = [tex]2\pi *4500=9000\pi[/tex] radian.

We know that ,

1 hour = 60 minute.

Angular speed = [tex]\frac{9000\pi radian}{60minute} =\frac{9000*3.14}{60}=471radian/minute[/tex]

Therefore, the angular speed of the blade is [tex]471[/tex] radian per minute.

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