please answer this exponents and powers question

Answer:
(a) 2
Step-by-step explanation:
[tex] (9^2 - 4^3) \times (\dfrac{-3}{17})^2 \times \dfrac{34}{9} = [/tex]
[tex] = (81 - 64) \times \dfrac{(-3)^2}{(17)^2} \times \dfrac{34}{9} [/tex]
[tex] = 17 \times \dfrac{9}{17 \times 17} \times \dfrac{2 \times 17}{9} [/tex]
[tex] = \dfrac{17 \times 9 \times 2 \times 17}{17 \times 17 \times 9} [/tex]
[tex] = \dfrac{17 \times 17 \times 9 \times 2}{17 \times 17 \times 9} [/tex]
[tex] = 2 [/tex]