Answer:
Resistance will be 13.824 ohm
And inductance will be 0.048 Henry
Explanation:
We have given real power P = 1500 watt
And apparent power S = 2500 VA
Voltage V = 240 volt
Frequency f = 60 Hz
Power factor [tex]cos\Phi[/tex] is given by
[tex]cos\Phi =\frac{P}{S}=\frac{1500}{2500}=0.6[/tex]
And real power is given by [tex]P=VIcos\Phi[/tex]
So [tex]1500=240\times I\times 0.6[/tex]
I = 10.4166 A
Now impedance [tex]Z=\frac{V}{I}=\frac{240}{10.4166}=23.04ohm[/tex]
And [tex]cos\Phi =\frac{R}{Z}[/tex]
So [tex]0.6=\frac{R}{23.04}[/tex]
R = 13.824 ohm
Impedance is given by [tex]Z=\sqrt{R^2+X_L^2}[/tex]
[tex]23.04=\sqrt{13.824^2+X_L^2}[/tex]
Squaring both side
[tex]530.84=191.10+X_L^2[/tex]
[tex]X_L=18.43ohm[/tex]
[tex]18.43=2\times 3.14\times 60\times L[/tex]
L = 0.048 Henry
