Answer:
The answer is 80,1 °C
Explanation:
Let´s start from the mass of the sample and the heat capacities:
First of all, we must calculate an average heat capacity. That's because we have a mixture and it is unknown the heat capacity of the whole sample.
The way we should do this calculation is as follows:
(1) [tex]H_{average}=Mass Fraction_{first component}* H_{first component}+MassFraction_{secondcomponent}*H_{second component}[/tex]
For example, the mass fraction of Fe is simply:
(2) [tex]MassFraction_{Fe}=\frac{10g Fe}{10g Fe + 10gTi}=0.5[/tex]
If you combine the equations (1) and (2) you have:
(3) [tex]H_{average}=0.5*0.461+0.5*0.544=0.5025\frac{J}{g-K}[/tex]
Once calculated the average heat capacity we can solve the problem taking into account the corresponding equation:
(4) [tex]Q=m*H_{average}*(T_2-T_1)[/tex]
Remember that:
Q: Heat gained or lost
m: Mass of the sample you want to analize
[tex]H_{average}[/tex] : The value obtained in equation (3)
[tex]T_2[/tex]: Final temperature of the sample
[tex]T_1[/tex]: Initial temperature of the sample
Now we must replace the problem data in equation (4)
Take into account:
Now we are ready to use equation (4):
(5) [tex]-200J=20g*0.5025\frac{J}{g*K} *(T_2-373K)[/tex]
It is clear that the unknown in equation (5) is [tex] T_2 [/tex]
The next step is to calculate [tex] T_2 [/tex]. Don't forget the signs; these are important.
Key concept: Since the system is loosing heat, the final temperature of the system ( [tex] T_2 [/tex]) should be lower than the initial temperature ( [tex] T_1 [/tex] )
Answer:
80,1
Explanation:
write the equation out and see what is what and then do the math
