Answer:
[tex]\large\boxed{\dfrac{16g^2}{3h^3}}[/tex]
Step-by-step explanation:
[tex]\dfrac{\frac{h}{3g^4}}{\frac{h^4}{16g^6}}=\dfrac{h}{3g^4}:\dfrac{h^4}{16g^6}=\dfrac{h}{3g^4}\cdot\dfrac{16g^6}{h^4}\\\\=\dfrac{16}{3}\cdot\dfrac{h}{h^4}\cdot\dfrac{g^6}{g^4}\\\\=\dfrac{16}{3}\cdot\dfrac{h\!\!\!\!\diagup}{h^{4\!\!\!\!\diagup^3}}\cdot\dfrac{g^{6\!\!\!\!\diagup^2}}{g^4\!\!\!\!\!\!\diagup}\\\\=\dfrac{16}{3}\cdot\dfrac{1}{h^3}\cdot\dfrac{g^2}{1}\\\\=\dfrac{16g^2}{3h^3}[/tex]
