Answer:
C. [tex]f(x)=4x^3+6x^2-x[/tex]
Step-by-step explanation:
Lets plug in -2 into each of these equation to see which one gives us the solution of -6
A. [tex]f(x)=x^3+x[/tex]
[tex]f(-2)=(-2)^3+(-2)\\\\f(-2)=-8-2\\\\f(-2)=-10[/tex]
B. [tex]f(x)=x^4-5x[/tex]
[tex]f(-2)=(-2)^4-5(-2)\\\\f(-2)=16+10\\\\f(-2)=26[/tex]
C. [tex]f(x)=4x^3+6x^2-x[/tex]
[tex]f(-2)=4(-2)^3+6(-2)^2-(-2) \\\\f(-2)=4(-8)+6(4)+2\\\\f(-2)=-32+24+2\\\\f(-2)=-6[/tex]
D. [tex]f(x)=-3x^3-4x^2+4x[/tex]
[tex]f(-2)=-3(-2)^3-4(-2)^2+4(-2)\\\\f(-2)=-3(-8)-4(4)-8\\\\f(-2)=24-16-8\\\\f(-2)=0[/tex]
As we can see, function C was the only one that gave us the value of -6, so that is our answer.
