A child has a toy tied to the end of a string and whirls the toy at constant speed in a horizontal circular path of radius R. The toy completes each revolution of its motion in a time period T. What is the magnitude of the acceleration of the toy?a. g
b. 2πg
c. Zero
d. 4π²R/T²
e. πR/T²

Respuesta :

Answer:

d. [tex]\frac{4\pi^{2} R}{T^{2}}[/tex]

Explanation:

[tex]R[/tex] = Radius of the circular path

[tex]T[/tex] = Time period of motion

[tex]w[/tex] = Angular speed of the motion

Angular speed of the motion is given as

[tex]w = \frac{2\pi }{T}[/tex]

The toy is moving in a circle and hence centripetal acceleration acts on it which can be given as

[tex]a = R w^{2} \\a = R (\frac{2\pi }{T})^{2}\\a = \frac{4\pi^{2} R}{T^{2}}[/tex]

hence the correct choice is

d. [tex]\frac{4\pi^{2} R}{T^{2}}[/tex]