Answer:
0.0364 m
Explanation:
[tex]D[/tex] = Screen distance = 2.10 m
[tex]d[/tex] = Slit width = 0.0328 mm = 0.0328 x 10⁻³ m
[tex]\lambda[/tex] = Wavelength of light = 568 x 10⁻⁹ m
[tex]w[/tex] = width of the central diffraction peak
Width of the central diffraction peak is given as
[tex]w = \frac{D \lambda}{d} \\w = \frac{(2.10) (568\times10^{-9})}{0.0328\times10^{-3}}\\w = 0.0364 m[/tex]
