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What is the pressure on a horizontal surface with an area of 8 msquared that is 4 m​ underwater? Use 1000 kg divided by m cubed for the density of water and 9.8 m divided by s squared for the acceleration due to gravity. What is the correct relationship to use to find the pressure on the horizontal​ surface?

Respuesta :

Answer:

140525 pa

Explanation:

[tex]h[/tex] = depth of water = 4 m

[tex]A[/tex] = Area of surface = 8 m²

[tex]\rho[/tex] = Density of water = 1000 kg m⁻³

tex]g[/tex] = acceleration due to gravity = 9.8 ms⁻²

[tex]P_{o}[/tex] = Atmospheric pressure = 101325 Pa

[tex]P[/tex] = Pressure at the given depth "h"

Pressure at the given depth is given as

[tex]P = P_{o} + \rho g h\\P = 101325 + (1000) (9.8) (4)\\P = 140525 pa[/tex]