Answer:
X2 - X2'=3.24×10⁻⁴m
Explanation:
Given Data
λ1=730nm=
λ2=640nm
d=0.61 mm
D=1.1 m
Distance of the second bright fringe from the central fringe is given by
Xn = = D x n x2 λ / d
X2 = 2 D λ1 / d
X2' = 2 D λ2 / d
Separation between the second bright fringes of the two wavelengths ( the separation between the second order fringes ) is ,
X2 - X2' = 2 D ( λ1 - λ2 ) / d
X2 - X2'= {2 x 1. 1 (730×10^-9 - 640×10^-9) }/ 0.61 x 10 ^-3
X2 - X2'=3.24×10⁻⁴m
