Respuesta :
[tex]\frac{142 - (3^{3} - 36+2)^{2} }{10+3(10-6)+27/3} =\\\\\\142 - (3^{3} - 36+2)^{2} = 142 - (27-36+2)^{2} = 142 +7^{2} = 142 + 79 = 221\\\\10+3(10-6)+27/3 = 10 + 3 (4) + 9 = 10 + 12 + 9 = 31\\\\\frac{221}{31} = 7\frac{4}{31}[/tex]
[tex]\frac{142 - (3^{3} - 36+2)^{2} }{10+3(10-6)+27/3} =\\\\\\142 - (3^{3} - 36+2)^{2} = 142 - (27-36+2)^{2} = 142 +7^{2} = 142 + 79 = 221\\\\10+3(10-6)+27/3 = 10 + 3 (4) + 9 = 10 + 12 + 9 = 31\\\\\frac{221}{31} = 7\frac{4}{31}[/tex]