Answer:
Apply Newton’s Second Law in the direction towards the radius of the curve.
[tex]F = ma_{rad} = \frac{mv^2}{R}\\F = F_{friction}\\F_{friction} = \frac{mv^2}{R}[/tex]
[tex]\mu mg = \frac{mv^2}{R}\\v = \sqrt{\mu Rg} = \sqrt{0.171\times 9.8 \times 88.9} = 148.97~m/s[/tex]
Explanation:
On the exit curve, the car is making circular motion. The only force that balances its centripetal force is the force of friction. Otherwise, the car would slide off the road.
