Respuesta :
Answer:
[tex]\lambda=4.143\times 10^{-7}\ m[/tex]
Explanation:
It is given that,
Energy of the photon, [tex]E=3\ eV=3\times 1.6\times 10^{-19}\ J[/tex]
[tex]E=4.8\times 10^{-19}\ J[/tex]
Let [tex]\lambda[/tex] is the wavelength of the photon. The energy of a photon is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
[tex]\lambda=\dfrac{hc}{E}[/tex]
[tex]\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{4.8\times 10^{-19}}[/tex]
[tex]\lambda=4.143\times 10^{-7}\ m[/tex]
So, the wavelength of the photon is [tex]\4.143\times 10^{-7}\ m[/tex]. Hence, this is the required solution.
