Predict the carboxylic acid product of the following reaction:CH3COOCH2CH3ethyl ethanoate+H2OH+⟶carboxylic acid+CH3CH2OHethanolExpress your answer using the IUPAC name.

First select the longest possible carbon chain.
The longest possible carbon chain should include the carbons of double or triple bonds.
The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and carboxylic acid by adding the suffix -oic acid.
The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.
The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.

For the given chemical reaction, the equation follows:

[tex]CH_3COOCH_2CH_3+H_2O\rightarrow CH_3COOH+CH_3CH_2OH[/tex]

When hydrolysis of ester takes place, it leads to the formation of an alcohol and a carboxylic acid.

So, when hydrolysis of ethyl ethanoate occurs, it produces ethanol and a 2- Carbon carboxylic acid named as ethanoic acid.

Hence, the IUPAC name of the carboxylic acid formed is ethanoic acid.