Answer:
the sample undergo [tex]1.67 \times 10^5[/tex] disintegrations per second.
Explanation:
Given:
The amount of sulphur purchased is 0.671 μCi
To find:
disintegrations per second = ?
Solution:
Some of the conversions are
[tex]1 Ci = 3.8 \times 10^{10} Bq[/tex]
1 rad = 0.01 Gy
1Gy = 1 j/kg tissue
1 rem = 0.01 Sv
1Sv = 1 j/Kg
Using these conversions,
The decay rate of this sample is calculated as
[tex]0.671 \mu C i \times \frac{1 \mu C i}{10^{6}} \mu C i \times \frac{0.671 \times 10^{10}}{1 \mu C i}[/tex]
= [tex]1.67 \times 10^5[/tex] disintegrations per second
