Respuesta :
Answer:
The value of the ratio of the rate constant is [tex]4.02\times10^{-3}[/tex]
Explanation:
Given that,
Energy = 52.1 kJ/mole
Initial temperature = 175°C
Final temperature = 75°C
We need to calculate the ratio of the rate constant change
Using formula of rate constant
[tex]\dfrac{k_{2}}{k_{1}}=\dfrac{E}{R}(\dfrac{1}{T_{2}}-\dfrac{1}{T_{1}})[/tex]
Where. T₁= initial temperature
T₂ = final temperature
E = energy
R = gas constant
Put the value into the formula
[tex]\dfrac{k_{2}}{k_{1}}=\dfrac{52.1}{8.31}(\dfrac{1}{273+75}-\dfrac{1}{273+175})[/tex]
[tex]\dfrac{k_{2}}{k_{1}}=0.00402[/tex]
[tex]\dfrac{k_{2}}{k_{1}}=4.02\times10^{-3}[/tex]
Hence, The value of the ratio of the rate constant is [tex]4.02\times10^{-3}[/tex]
