Answer:2625 ways
Step-by-step explanation:
Given
There are 7 males , 5 Females and 6 children
There are 3 males Roles, 1 Female and 2 child roles available
No of ways in which 3 males can be chosen [tex]=^{7}C_3=35\ ways[/tex]
No of ways in which 1 Female can be chosen [tex]=^{5}C_1=5\ ways[/tex]
No of ways in which 2 children can be chosen [tex]=^{6}C_2=15\ ways[/tex]
Total no of ways[tex]=35\times 5\times 15=2625\ ways[/tex]
